Object at r ——-Light sensing of moving objects ———– (seen as) S
r —— Cosine (wt) + i sine (wt) ——– S = r [cosine (wt) + i sine (wt)]
Particle ————————- Light —————————— Wave
Newton ——– Kepler’s Time dependent ——– Newton’s Time dependent

A-Special theory of relativity

1-Lenght contraction

Line of Sight: r cosine wt: light aberrations
A moving object with velocity v will have when visualized through light sensing a light aberration angle (wt); w = constant and t= time

Also, sine wt = v/c; cosine wt = √ [1-sine² (wt)] = √ [1-(v/c) ²]
Where v = velocity; c = light velocity
A visual object moving with velocity v will be seen as S
S = r [cosine (wt) + i sine (wt)] = r Exp [i wt]; Exp = Exponential

S = r [√ [1-(v/c) ²] + ỉ (v/c)] = S x + i S y

S x = Visual location along the line of sight = r [√ [1-(v/c) ²]

This Equation is special relativity Length Contraction formula and it is just the visual effects and caused by light aberrations of a moving object along the line of sight.

In a right angled velocity triangle A B C: Angle A = wt
Angle B = 90°; Angle C = 90° -wt
AB = hypotenuse = c; BC = opposite = v; CA= adjacent = c √ [1-(v/c) ²]

2- Time dilatations
Along the line of sight; S x = r cosine wt
Hypotenuse = S x = [c t x] = c t √ [1-(v/c) ²];
Where t = self time; t x = time by others

t x = t √ [1-(v/c) ²]; and
t = {1/√ [1-(v/c) ²]} t x

These are time dilatation equations given by Einstein’s special relativity theory.

3- Δ E= mc²

S = r Exp (ỉ ω t); sin ω t =v/c; v = c sin ω t; r = -(c/ω) cosine ω t;
And r. v = (-c²/ω) sin ω t cosine ω t

P = d S/d t = (v + ỉ ω r) Exp (ỉ ω t); v² = c² sin² ω t; ω² r² = c² cosine² ω t
P² = (v + ỉ ω r). (v + ỉ ω r) Exp [2(ỉ ω t)] = [v² -ω² r² +2ỉ ω (r. v)] Exp [2(ỉ ω t)]

P² = [c² sin² ω t - c² cosine² ω t - 2c²ỉ sin ω t cosine ω t] Exp [2(ỉ ω t)]
P² = – c² [cosine² ω t - sin² ω t + ỉ sin 2ω t] Exp [2(ỉ ω t)]

P² = -c² Exp [4(ỉ ω t)]
E = mP²/2 = – mc²/2 [cosine² 2ω t - sin² 2ω t + 2ỉ sin 2ω t cosine 2ω t]

E = (-mc²/2) {1-2sin² 2ω t + 2ỉ [1- 2sin² ω t] 2[sin ω t cosine ω t]}
E = (-mc²/2) {1- 2(v/c) ² + 4ỉ [1- 2(v/c) ²] (v/c) √ [1- (v/c) ²]}

If v = 0 then E (1) = (-mc²/2); and
If v = c then E (2) = (mc²/2) then

Δ E = E (2) – E (1) = (mc²/2) – (-mc²/2)
Δ E = mc²

B- General Theory of relativity

What is the visual effect for angular velocity along the line of sight? At Perihelion It is called the Advance of perihelion. Let us derive that

Areal velocity is constant: r² θ’ =h Kepler’s Law

h = 2π a b/T; b=a√ (1-ε²); a = mean distance value; ε = eccentricity
S = r Exp (ỉ wt); r² θ’= h = S² w’

h = S²w’= [r² Exp (2iwt)] w’=r²θ’; w’ = (θ’) exp [-2(ỉ wt)]
And w’= (h/r²) [cosine 2(wt) - ỉ sine 2(wt)] = (h/r²) [1- 2sine² (wt) - ỉ sin 2(wt)]

With w’ = w’ (x) + ỉ w’(y); w’(x) = (h/r²) [1- 2sine² (wt)]
Δ w’= w’(x) – (h/r²) = – 2(h/r²) sine² (wt) = – 2(h/r²) (v/c) ² v/c=sine wt

Angular velocity (h/ r²) (Perihelion/Periastron) = [2πa.a√ (1-ε²)]/Ta² (1-ε) ²= [2π√ (1-ε²)]/T (1-ε) ²

Δ w’ = [w'(x) – h/r²] = -4π {[√ (1-ε²)]/T (1-ε) ²} (v/c) ² radian per second
[180/π; degrees][100years=36526days; century] x [3600; seconds in degree]

Δ w” = (-720x36526x3600/T) {[√ (1-ε²]/(1-ε)²} (v/c)² seconds of arc per century

This equation gives the rate of advance of perihelion of Mercury with better results than all of Albert Einstein’s publications and better than all of published physics.

The circumference of an ellipse: 2πa (1 – ε²/4 + 3/16(ε²)²- –.) ≈ 2πa (1-ε²/4); R =a (1-ε²/4)
v=√ [G m M / (m + M) a (1-ε²/4)] ≈ √ [GM/a (1-ε²/4)]; m<<M; Solar system

1- Advance of Perihelion of mercury.

G=6.673×10^-11; M=2×10^30kg; m=.32×10^24kg
ε = 0.206; T=88days; c = 299792.458 km/sec; a = 58.2km/sec
Calculations yields:
v =48.14km/sec; [√ (1- ε²)] (1-ε) ² = 1.552
Δ w”= (-720x36526x3600/88) x (1.552) (48.14/299792)²=43.0”/century

2- DI Herculis Apsidal motion solution: derived from S= r exp [ỉ ω t]
(See other articles by Joe Nahhas)

W° (ob) = (-720×36526/T) x {[√ (1-ε²)]/ (1-ε) ²} [(v*/c) + (v°/c)] ² degrees/ century

Where v* = v (center of mass) = 106.38km/sec; v° (spin difference) = 0
T = orbital period; ε = eccentricity; c =light speed

Application 3: Gravitational red shift: Pound Rebka Experiment

S = r Exp [î ω t]

1/S = 1/r Exp [-ỉ ω t]
And λ (S) = λ (r) Exp [-ỉ ω t]; λ = wavelength

Then υ(s) = υ(r) Exp [ỉ ω t]; υ = frequency
And υ(S) = υ (r, t) = υ(r, 0) υ (0, t) = υ(r) υ (0, t)
With sin ω(r) t = v/c; cosine ω(r) t = √ [1-(v/c) ²]

Then υ (r, t) = υ(r, 0) {√ [1-(v/c) ²] + ỉ (v/c)} = Real {υ(r, t)} + Imaginary {υ(r, t)}
Real {υ (r, t)} = υ (r, 0) √ [1-(v/c) ²] ≈ υ (r, 0) [1 - 1/2(v/c) ²]

Δ υ (r, t) = real {υ (r, t)} – υ (0, t)
Δ υ (r, t) = -υ (r, 0)/2 [(v/c) ²]
Δ υ(r, t)/υ(r, 0) = -1/2(v/c)²[up]-{1/2(v/c)²[down]} = – (v/c) ²
v² = 2gh; g = 9.81km/s² gravitational acceleration; h = height

Δ υ/υ [Total] =-[2gh/c²]
4- Light bending: Lord Edenton experiment
S = r Exp [ỉ ω t]; From Kepler's Equation: r² θ' = h = 2A/T
h = S²(r, t) θ'(r, t) = r² (θ, t) θ' (θ, t) = r² (θ, 0) Exp [2ỉ ω t] θ' (θ, t) = 2A/t
And θ' (θ, t) = θ' (θ, 0) θ'(0, t) = [h/ r² (θ, 0)] Exp [-2ỉ ω(r) t]
Then θ '(θ, t) = [2A/t r² (θ, 0)] {1 – 2sin²ω(r) t – 2ỉ sin ω(r) t cosine ω(r) t}
Now [t θ'(θ, t)] = [2A/r² (θ' 0)] [1 - 2sin²ω(r) t] -2ỉ [2A/r² (θ, 0)] [sin ω(r) t cosine ω(r) t]
= Δ x + i Δ y
Δ θ = Δ x – [A/r² (θ, 0)] = – [A/r² (θ, 0)][4sin²ω(r)t]; sin ω(r)t = v/c
Δ θ = – [A/r² (θ, 0)](v/c) ²
(v/c) ² ≈ 1.75"; v² = GM/R; G = Gravitational constant; M = Sun mass; R = sun radius
Δ θ = [A/r² (θ, 0)] [1.75"]; A = area
The values depend on near by stars and the measured values fit this equation.
Russians in 1936; Δ θ = 2.74
[A/r² (θ, 0)] = π/2
Δ θ = π/2(1.75") = 2.74"

Application 5: Shapiro time delay (Vikings 6, 7; 1977)
Mars ————————— Middle—- Sun ————- Earth
The center of mass is the sun. The sun produces a velocity field given by
v = √ [GM/a (1- ε²/4)]
From above t =2 arc length/c=2d Δ w/c = (8π r/c) (v/c) ²; Δ w=4π (v/c) ²; r = 2a=d
t = 16πGM/c³ (1-ε²/4); ε = [a (1) -a (2)]/ [a (1) + a (2)] = .2075
t = (8πd/c) (v/c) ²= 8π (377,536,987.5/299792.458) (26.6575872/299792.458)²=250μs
If d = 2a (1-ε²/4), then t = 247.597μs value theorized actual measured value is 250μs
All this is not due to space-time but due to light aberration caused by moving planets.
θ'(0,0) = h(0,0)/r²(0,0) = 2π/T
θ' (0,t) = θ'(0,0)Exp(-2ỉwt)={2π/T} Exp (-2iwt)
θ'(0,t) = θ'(0,0) [cosine 2(wt) - ỉ sine 2(wt)] = θ'(0,0) [1- 2sine² (wt) - ỉ sin 2(wt)]
θ'(0,t) = θ'(0,t)(x) + θ'(0,t)(y); θ'(0,t)(x) = θ'(0,0)[ 1- 2sine² (wt)]
θ'(0,t)(x) – θ'(0,0) = – 2θ'(0,0)sine²(wt) = – 2θ'(0,0)(v/c)² v/c=sine wt; c=light speed
T [θ'(0, t) - θ'(0, 0)] = -4π (v/c) ²
Δ θ = -4π (v/c) ² Earth-Mars
Sun-Photon:
The circumference of an ellipse: 2πa (1 – ε²/4 + 3/16(ε²)²—) ≈ 2πa (1-ε²/4); R =a (1-ε²/4)
v=√ [Gm M/ (m + M) a (1-ε²/4)] ≈ √ [GM/a (1-ε²/4)]; m<<M; Solar system
ΔΓ = 2 arc length/c = 2[Δ θ] 2d/c = 2[- 4π (v/c) ²] 2d/c; ΔΓ = -8πd/c (v/c) ²;
ΔΓ = 8πd/c³ [GM/a (1-ε²/4)] =16πGM/c³ (1-ε²/4) = Γ0 (1 – ε²/4)
ε = [a (planet 1) - a (planet 2)]/ [a (planet 1) + a (planet 2)] =0.2075 Mars-Earth
Γ0 = 16 πGM/c³= 247.5974607μs=universal constant; ΔΓ = 250μs Mars-Earth.
Joe nahhas1958@yahoo.com All right reserved

Been away for a while, but so glad people are still interested.

You are correct, and both ideas do in fact collaborate each other.
Theirs is more detailed, but also more expensive and complicated.
The whole idea behind the experiment and blog is to understand the origin of mass, and in particular, “rest mass”.
The cheapest and simplest way to understand this is to understand the geometrical interpretation of (E=mc squared) as (E=mc circled) or E=mc sphered in 3d.
Not that the big expensive experiments, such as the LHC (Large Hadron Collide r), and the computer experiment in this article are not worth it, after all they do provide lots of jobs, promote international cooperation between scientist, as well as doing things that a single individual could not. But just as garbage in leads to garbage out, for computer experiments, and inaccurate and incomplete basic assumptions such as “frequency leads to v2, interpreted as infinity, instead of c2, which is rest mass, through energy in circular and or spherical rotation, sometimes a self taught individual, without such basic assumptions, thinking outside the box, can see from a deeper foundation, a fuller scope of a problem, and find the solution.
This is in and of itself a lesson to be learned in the advancement of physics as well as any other subject.
Beside it can bolster confidence in the individual mind, for finding things that the large expensive machines could not. Furthermore, I being an “African American”, it may even bolster more confidence in minorities just as Barrack Obama’s election has. And God knows that we all need more confidence in ourselves and each other.
People have lots of competitive time, money, and pride invested in these expensive projects of conventional physics, and I understand the reluctance to share and acknowledge credit for such a competitive task. But sooner or latter it will be acknowledged, and it will be on record who does and who doesn’t, and people will be asking for explanations.
At a time such as this, when the world needs the truth about the world and our place in it, so that we may act more in accord with it, can we afford to be more concerned about whose right than whats is right?
The truth is the truth, with or without me, as well as with or without people titles and or degrees. It should be our focus more than who discovered it first.
I just thank God that I had the privilege to be the one to discover this, and give all the glory to God, only hoping to be acknowledged because in this world we need a certain measure of acknowledgment. But more importantly, we need to acknowledge the creative principle of the universe itself.
May the truth prevail over those and that which seek to obscure it.

Conrad J Countess

I get the concept, if not the math. You’re saying that matter is energy spinning at the speed of light, and that the spin is creating mass.

What the article is saying (way up there at the top of the page) is that it is the interactions of gluons and quarks, as well as gluons ‘popping into and out of existence’ that create mass.

With all due respect, it sounds as though QCD theory is a more detailed explanation of the same phenomenon.

It takes a certain amount of incite to understand (E=mc^2) = (E=mc^circled), but if you look at my web site explaining it you would see that I am right.http://docs.google.com/Doc?id=dsn5q6f_101hgtjv9fb&hl=en

The speed of light squared or (c^2), geometrically is c in the linear direction times c in the 90 degree angular direction, which is analogous to (a line of 1 inch in the linear direction times a line of 1 inch in the 90 degree or vertical direction to create a square inch). But it is also analogous to a centrifugal force being balanced by a centripetal force at a 90 degree angle to it to create circular motion. Matter or rest mass is created from energy in circular and or spherical motion and c^2 is where this transformation of energy to matter takes place. E=mc^2 or energy equals rest mass at the mathematical conversion factor of (c^2) precisely because (c^2) is not just a mathematical conversion factor of energy to matter, but is an actual conversion frequency at high end of EM spectrum, where energy turns to matter. This is because at this frequency/wavelength, energy takes on a circular and or spherical form. I don’t mind explaining it to anyone who still doesn’t understand it, and I don’t take offense to anyone thinking that it is funny. Not because I know that I will get the last laugh, because I am not the type to brag with I told you so, but because I know how hard it is to accept revolutionary ideas. But if anyone looks at this objectively, which is how science is suppose to be done, you will see too that it is true, and there is no way around it.

Conrad