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	<title>Comments on: Giving Vega a spin</title>
	<atom:link href="http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/feed/" rel="self" type="application/rss+xml" />
	<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/</link>
	<description>I am an astronomer, writer, and skeptic. I likes reality the way it is, and I aims to keep it that way. My real name is Phil Plait, and I run the Bad Astronomy blog.</description>
	<lastBuildDate>Tue, 14 Feb 2012 15:05:27 +0000</lastBuildDate>
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		<title>By: SFwriter</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13043</link>
		<dc:creator>SFwriter</dc:creator>
		<pubDate>Thu, 23 Mar 2006 23:23:24 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13043</guid>
		<description>Blake Stacey Said:
&quot;Itâ€™s all the sort of nonsense up with which we should not put.&quot;

I always liked Winston Churchill! :mrgreen:</description>
		<content:encoded><![CDATA[<p>Blake Stacey Said:<br />
&#8220;Itâ€™s all the sort of nonsense up with which we should not put.&#8221;</p>
<p>I always liked Winston Churchill! <img src='http://blogs.discovermagazine.com/badastronomy/wp-includes/images/smilies/icon_mrgreen.gif' alt=':mrgreen:' class='wp-smiley' /> </p>
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		<title>By: Irishman</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13042</link>
		<dc:creator>Irishman</dc:creator>
		<pubDate>Thu, 23 Mar 2006 22:56:31 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13042</guid>
		<description>In order for that to be the case, we would need to be aligned with the major axis of the ellipse.  But there is no reason the major axis would stay constant.  The distant objects would remain distant as they orbit, so the ellipse would rotate around Vega.  Thus we would not see a circular projection for very long, it would quickly* become an ellipse.

*Quickly in astronomical terms.  I don&#039;t know how fast the disk material is orbiting.</description>
		<content:encoded><![CDATA[<p>In order for that to be the case, we would need to be aligned with the major axis of the ellipse.  But there is no reason the major axis would stay constant.  The distant objects would remain distant as they orbit, so the ellipse would rotate around Vega.  Thus we would not see a circular projection for very long, it would quickly* become an ellipse.</p>
<p>*Quickly in astronomical terms.  I don&#8217;t know how fast the disk material is orbiting.</p>
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		<title>By: Greg Wilson</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13041</link>
		<dc:creator>Greg Wilson</dc:creator>
		<pubDate>Thu, 23 Mar 2006 22:54:36 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13041</guid>
		<description>My physics prof at UVa hated the word centrifugal and didn&#039;t care too much about centripetal.  His ideas were that centrifugal was just a result of inertia and that centripetal referred to too many separate forces, i.e. many things provide a centripetal force:  it&#039;s not &quot;one&quot; special force.   I think these are teaching subtleties to help students understand.
I agree with my prof. and think that centrifugal is truly a fictitious force because if suddenly the centripetal force were to disappear, then the object flies off in a straight line at constant velocity until another force acts on it.   If the centrifugal force was real, then the object should move in the direction of that force, i.e. if the gravitational force holding the star together (and providing the centripetal force) were to disappear, I don&#039;t think particles would fly off toward the outside.
I do however understand that it&#039;s sometimes beneficial when you&#039;re thinking about a rotating frame of reference to use &quot;centrifugal&quot; but deep down, I feel that it&#039;s fictitious.</description>
		<content:encoded><![CDATA[<p>My physics prof at UVa hated the word centrifugal and didn&#8217;t care too much about centripetal.  His ideas were that centrifugal was just a result of inertia and that centripetal referred to too many separate forces, i.e. many things provide a centripetal force:  it&#8217;s not &#8220;one&#8221; special force.   I think these are teaching subtleties to help students understand.<br />
I agree with my prof. and think that centrifugal is truly a fictitious force because if suddenly the centripetal force were to disappear, then the object flies off in a straight line at constant velocity until another force acts on it.   If the centrifugal force was real, then the object should move in the direction of that force, i.e. if the gravitational force holding the star together (and providing the centripetal force) were to disappear, I don&#8217;t think particles would fly off toward the outside.<br />
I do however understand that it&#8217;s sometimes beneficial when you&#8217;re thinking about a rotating frame of reference to use &#8220;centrifugal&#8221; but deep down, I feel that it&#8217;s fictitious.</p>
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		<title>By: Matt</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13040</link>
		<dc:creator>Matt</dc:creator>
		<pubDate>Thu, 23 Mar 2006 17:32:25 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13040</guid>
		<description>I have a question tangential to the centri[fug&#124;ped]al debate.

You mentioned that the apparently nearly circular disk of Vega&#039;s system is evidence that we are looking nearly pole-on to a circular system -- taken from the fact that if we looked obliquely at a circular system we&#039;d see an ellipse.

Okay, so how do we know we aren&#039;t looking at an elliptical system obliquely, yielding an almost-circle?</description>
		<content:encoded><![CDATA[<p>I have a question tangential to the centri[fug|ped]al debate.</p>
<p>You mentioned that the apparently nearly circular disk of Vega&#8217;s system is evidence that we are looking nearly pole-on to a circular system &#8212; taken from the fact that if we looked obliquely at a circular system we&#8217;d see an ellipse.</p>
<p>Okay, so how do we know we aren&#8217;t looking at an elliptical system obliquely, yielding an almost-circle?</p>
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		<title>By: SFReader</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13039</link>
		<dc:creator>SFReader</dc:creator>
		<pubDate>Thu, 23 Mar 2006 15:36:52 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13039</guid>
		<description>Another reason for Vega&#039;s spin might be that it&#039;s in the process of collapsing, or perhaps coalescing, which will be interesting for us, being so close.  Although that&#039;s not predicted by its place on the stellar life chart, is it?</description>
		<content:encoded><![CDATA[<p>Another reason for Vega&#8217;s spin might be that it&#8217;s in the process of collapsing, or perhaps coalescing, which will be interesting for us, being so close.  Although that&#8217;s not predicted by its place on the stellar life chart, is it?</p>
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		<title>By: HawaiiArmo</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13038</link>
		<dc:creator>HawaiiArmo</dc:creator>
		<pubDate>Thu, 23 Mar 2006 09:11:23 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13038</guid>
		<description>I was thinking about the possibilities that arose regarding the current understanding of stellar evolution and how it applies to Vega&#039;s extremely rapid angular spin.  Apparently, some rotational force, some shock or another provides enough torque to cause a cold molecular cloud to condense and begin spinning.  Perhaps Vega was located close to a supernova, and the energy imparted upon its inception resulted in the high rate of angular motion.
Does anyone else have any theories regarding the possible reason for Vega&#039;s high rate of spin?  Perhaps we can have an informal discussion, because I doubt there are any simulations that present Vega&#039;s stellar origin in regards to this new data.</description>
		<content:encoded><![CDATA[<p>I was thinking about the possibilities that arose regarding the current understanding of stellar evolution and how it applies to Vega&#8217;s extremely rapid angular spin.  Apparently, some rotational force, some shock or another provides enough torque to cause a cold molecular cloud to condense and begin spinning.  Perhaps Vega was located close to a supernova, and the energy imparted upon its inception resulted in the high rate of angular motion.<br />
Does anyone else have any theories regarding the possible reason for Vega&#8217;s high rate of spin?  Perhaps we can have an informal discussion, because I doubt there are any simulations that present Vega&#8217;s stellar origin in regards to this new data.</p>
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		<title>By: ioresult</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13037</link>
		<dc:creator>ioresult</dc:creator>
		<pubDate>Thu, 23 Mar 2006 04:49:02 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13037</guid>
		<description>BA said: &quot;Good thing I donâ€™t plan any Mars probes.&quot;

Mixing pounds with newtons, that was waay bad!</description>
		<content:encoded><![CDATA[<p>BA said: &#8220;Good thing I donâ€™t plan any Mars probes.&#8221;</p>
<p>Mixing pounds with newtons, that was waay bad!</p>
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		<title>By: The Bad Astronomer</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13036</link>
		<dc:creator>The Bad Astronomer</dc:creator>
		<pubDate>Thu, 23 Mar 2006 01:13:01 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13036</guid>
		<description>Note that I said in the entry that 0.3% is due to the Earth&#039;s spin. I didn&#039;t want to complicate it by adding in anything else.

I also corrected my math error. I didn&#039;t convert miles to km! Amazing. Good thing I don&#039;t plan any Mars probes.</description>
		<content:encoded><![CDATA[<p>Note that I said in the entry that 0.3% is due to the Earth&#8217;s spin. I didn&#8217;t want to complicate it by adding in anything else.</p>
<p>I also corrected my math error. I didn&#8217;t convert miles to km! Amazing. Good thing I don&#8217;t plan any Mars probes.</p>
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		<title>By: Jim Hammond</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13035</link>
		<dc:creator>Jim Hammond</dc:creator>
		<pubDate>Thu, 23 Mar 2006 00:32:56 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13035</guid>
		<description>With a little research and calculation, it looks like the total difference in acceleration of gravity between the poles and the equator, at sea level, is about 0.6%. In this value about 0.34% comes from the rotational acceleration and 0.26% comes from the difference in mean sea level distance from the center of the earth.  Actually, its not just the distance but includes the effect of the distribution of the earth&#039;s mass.  A gravity change caused by the difference between the polar and equatorial radii would result in about a 0.66% effect by itself.

Back near the middle of the last century, I gave many talks on the subject of measuring the acceleration of gravity and I used to always use the 0.5% approximate value with about a 50/50 split between the two effects.  It was not quite true.</description>
		<content:encoded><![CDATA[<p>With a little research and calculation, it looks like the total difference in acceleration of gravity between the poles and the equator, at sea level, is about 0.6%. In this value about 0.34% comes from the rotational acceleration and 0.26% comes from the difference in mean sea level distance from the center of the earth.  Actually, its not just the distance but includes the effect of the distribution of the earth&#8217;s mass.  A gravity change caused by the difference between the polar and equatorial radii would result in about a 0.66% effect by itself.</p>
<p>Back near the middle of the last century, I gave many talks on the subject of measuring the acceleration of gravity and I used to always use the 0.5% approximate value with about a 50/50 split between the two effects.  It was not quite true.</p>
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		<title>By: The Bad Astronomer</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13034</link>
		<dc:creator>The Bad Astronomer</dc:creator>
		<pubDate>Wed, 22 Mar 2006 23:45:45 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13034</guid>
		<description>Mark, that&#039;s why I said &quot;high in the sky&quot;. It can be seen from pretty far south, but not high in the sky.</description>
		<content:encoded><![CDATA[<p>Mark, that&#8217;s why I said &#8220;high in the sky&#8221;. It can be seen from pretty far south, but not high in the sky.</p>
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		<title>By: Mark Hansen</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13033</link>
		<dc:creator>Mark Hansen</dc:creator>
		<pubDate>Wed, 22 Mar 2006 23:28:37 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13033</guid>
		<description>Not a big criticism, but we poor, benighted souls south of the equator CAN see Vega too! Lower in the sky, naturally, but still very visible. It gets a bit annoying when everything astronomically worthwhile is assumed to be only visible above the equator.</description>
		<content:encoded><![CDATA[<p>Not a big criticism, but we poor, benighted souls south of the equator CAN see Vega too! Lower in the sky, naturally, but still very visible. It gets a bit annoying when everything astronomically worthwhile is assumed to be only visible above the equator.</p>
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		<title>By: ioresult</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13032</link>
		<dc:creator>ioresult</dc:creator>
		<pubDate>Wed, 22 Mar 2006 23:26:15 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13032</guid>
		<description>I was wondering if, because of its very fast rotation, Vega did not emit an intense solar (vegan) wind. I imagine a lot of atmosphere would be ejected and then cool down as it leaves the star. Is there a possibility that the infrared we see could be emitted by this cooling ejected atmosphere instead of a disk of dust? And even if there really is a disk of dust, wouldn&#039;t it be blown away by the intense wind?</description>
		<content:encoded><![CDATA[<p>I was wondering if, because of its very fast rotation, Vega did not emit an intense solar (vegan) wind. I imagine a lot of atmosphere would be ejected and then cool down as it leaves the star. Is there a possibility that the infrared we see could be emitted by this cooling ejected atmosphere instead of a disk of dust? And even if there really is a disk of dust, wouldn&#8217;t it be blown away by the intense wind?</p>
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		<title>By: Jack Hagerty</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13031</link>
		<dc:creator>Jack Hagerty</dc:creator>
		<pubDate>Wed, 22 Mar 2006 22:58:31 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13031</guid>
		<description>Phil: Don&#039;t worry about Vega as depicted in &quot;Contact.&quot; After all, if Ellie Arroway was traveling the worm hole express from Earth, woudn&#039;t she likely pop out along the Sun-Vega line? That means that she&#039;d be looking at one of the poles of Vega, from which vantage point it still looks round.

I thought it interesting that the producers even put a debris field around the star.

- Jack

PS - If you have the DVD of the movie, watch the special feature on the making of the opening &quot;pullout&quot; sequence. On the image of Mars, the FX guys embedded Hogland&#039;s face. Well, not his actual face; it&#039;s the image he&#039;s been making a living off of for the past decade or so. Just another in-joke.</description>
		<content:encoded><![CDATA[<p>Phil: Don&#8217;t worry about Vega as depicted in &#8220;Contact.&#8221; After all, if Ellie Arroway was traveling the worm hole express from Earth, woudn&#8217;t she likely pop out along the Sun-Vega line? That means that she&#8217;d be looking at one of the poles of Vega, from which vantage point it still looks round.</p>
<p>I thought it interesting that the producers even put a debris field around the star.</p>
<p>- Jack</p>
<p>PS &#8211; If you have the DVD of the movie, watch the special feature on the making of the opening &#8220;pullout&#8221; sequence. On the image of Mars, the FX guys embedded Hogland&#8217;s face. Well, not his actual face; it&#8217;s the image he&#8217;s been making a living off of for the past decade or so. Just another in-joke.</p>
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		<title>By: Jack Hagerty</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13030</link>
		<dc:creator>Jack Hagerty</dc:creator>
		<pubDate>Wed, 22 Mar 2006 22:48:44 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13030</guid>
		<description>BA sez: &quot;Centripetal and centrifugal forces are the same thing. They are just seen in different reference frames. People argue endlessly about them, which I find very endlessely amusing. They are both real forces.&quot;

As I learned it back in high school physics (slightly after the Earth cooled), centrifugal force is cause by centripital acceleration. The radial acceleration is towards the center causing a force away from the center.

- Jack</description>
		<content:encoded><![CDATA[<p>BA sez: &#8220;Centripetal and centrifugal forces are the same thing. They are just seen in different reference frames. People argue endlessly about them, which I find very endlessely amusing. They are both real forces.&#8221;</p>
<p>As I learned it back in high school physics (slightly after the Earth cooled), centrifugal force is cause by centripital acceleration. The radial acceleration is towards the center causing a force away from the center.</p>
<p>- Jack</p>
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		<title>By: Stars Over Kansas &#187; Astro News Roundup March 22</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13029</link>
		<dc:creator>Stars Over Kansas &#187; Astro News Roundup March 22</dc:creator>
		<pubDate>Wed, 22 Mar 2006 22:06:26 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13029</guid>
		<description>[...] Phil Plait &#8220;The Bad Astronomer&#8221; gets into a spin about Sirius. [...]</description>
		<content:encoded><![CDATA[<p>[...] Phil Plait &#8220;The Bad Astronomer&#8221; gets into a spin about Sirius. [...]</p>
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		<title>By: The Bad Astronomer</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13028</link>
		<dc:creator>The Bad Astronomer</dc:creator>
		<pubDate>Wed, 22 Mar 2006 21:32:27 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13028</guid>
		<description>Michael, thanks. I corrected the orange plus thing. :-) I&#039;ll check my math again when I get a chance.</description>
		<content:encoded><![CDATA[<p>Michael, thanks. I corrected the orange plus thing. <img src='http://blogs.discovermagazine.com/badastronomy/wp-includes/images/smilies/icon_smile.gif' alt=':-)' class='wp-smiley' />  I&#8217;ll check my math again when I get a chance.</p>
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		<title>By: Jim Hammond</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13027</link>
		<dc:creator>Jim Hammond</dc:creator>
		<pubDate>Wed, 22 Mar 2006 21:17:42 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13027</guid>
		<description>If the following points are clarified in previous comments, I apologize for not finding those clarifications.  Note: There doesn&#039;t seem to be such a word as &quot;centripedal&quot; in my dictionary.

Your weight at sea level at the equator is about 0.5% lower than it is at the poles.  About half of the difference is due to the centrifugal effect and about half is due to the spheroidal shape of the earth, also caused by the centrifugal effects.  Thus, because you are farther from the center of the earth, the effective force of gravity is lower at sea level on the equator than at the poles.  The acceleration of gravity (which by convention, includes centrifugal effects) changes by about one part in a million for every every ten feet change in altitude.  Thus, you also weigh about 0.3% less at the summit of Mt. Everest (not that I&#039;ve been there) than you do at sea level at the same latitude.  Gravity provides the centripetal force toward the center of the earth.  This, of course, is far larger than the force needed to overcome the tendancy for the rotation to throw you off the earth.</description>
		<content:encoded><![CDATA[<p>If the following points are clarified in previous comments, I apologize for not finding those clarifications.  Note: There doesn&#8217;t seem to be such a word as &#8220;centripedal&#8221; in my dictionary.</p>
<p>Your weight at sea level at the equator is about 0.5% lower than it is at the poles.  About half of the difference is due to the centrifugal effect and about half is due to the spheroidal shape of the earth, also caused by the centrifugal effects.  Thus, because you are farther from the center of the earth, the effective force of gravity is lower at sea level on the equator than at the poles.  The acceleration of gravity (which by convention, includes centrifugal effects) changes by about one part in a million for every every ten feet change in altitude.  Thus, you also weigh about 0.3% less at the summit of Mt. Everest (not that I&#8217;ve been there) than you do at sea level at the same latitude.  Gravity provides the centripetal force toward the center of the earth.  This, of course, is far larger than the force needed to overcome the tendancy for the rotation to throw you off the earth.</p>
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		<title>By: P. Edward Murray</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13026</link>
		<dc:creator>P. Edward Murray</dc:creator>
		<pubDate>Wed, 22 Mar 2006 20:58:15 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13026</guid>
		<description>Jean-Denis your English is just fine, far better than some Americans&#039;
English!:)</description>
		<content:encoded><![CDATA[<p>Jean-Denis your English is just fine, far better than some Americans&#8217;<br />
English!:)</p>
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		<title>By: Blake Stacey</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13025</link>
		<dc:creator>Blake Stacey</dc:creator>
		<pubDate>Wed, 22 Mar 2006 20:43:16 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13025</guid>
		<description>P.S. The &lt;a href=&quot;http://www.obscure.org/physics-faq/General/Centrifugal/centri.html&quot; rel=&quot;nofollow&quot;&gt;Physics FAQ&lt;/a&gt; does a pretty good job of treating the whole centri-whatever issue.</description>
		<content:encoded><![CDATA[<p>P.S. The <a href="http://www.obscure.org/physics-faq/General/Centrifugal/centri.html" rel="nofollow">Physics FAQ</a> does a pretty good job of treating the whole centri-whatever issue.</p>
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		<title>By: Michael</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13024</link>
		<dc:creator>Michael</dc:creator>
		<pubDate>Wed, 22 Mar 2006 20:30:04 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13024</guid>
		<description>I&#039;ll add to the nitpicking.  :p

Using Google as a calculator, and Nineplanets.org for dimensions:
275 km/sec = 615157 mph
Earth&#039;s circumference = 24901 mi
615157 / 24901 = 24.7 revolutions per hour
1 hour / 24.7 = 146 seconds per revolution, not 90.  :)

According to http://www.solstation.com/stars/vega.htm, the actual rotational period is 12.5 hours, which &quot;suggest that the star is rotating at about 92 percent of the speed (angular velocity) that would cause it to physically fly apart&quot;.

The orange &quot;+&quot; represents the &quot;subsolar point&quot;, according to the paper at the link Phil posted.  Doesn&#039;t that mean a line between the core of Vega and us passes through that point?  Which in turn means it&#039;s the center of the disc, as seen from here?

Finally, about the centripedal/centrifugal thing:  Not sure how it&#039;s &quot;officially&quot; defined, but it seems logical to me to use them for the correct forces.  Since centripedal means &quot;to the middle&quot;, it should refer to the major body pulling inward on the minor body (whether major/minor be star/planet, planet CoG/planet particle, or person/bucket of water).  Since centrifugal means &quot;away from the middle&quot;, it should refer to the minor body pulling outward on the major body.  Both are real, opposite forces that are actually present in any reference frame.  The direction may seem to change (so which is which might be hard to define without a defined reference point), but they are still different forces.  The inertial effect is what gives the forces meaning (otherwise they&#039;d both just instantly accelerate each other to infinity--or impact).

Like in a car: the centripedal force is the tires pulling the car towards the center of the corner, the centrifugal force is the car pushing the tires towards the edge of the road.  The inertial effect determines how much force the tires must overcome to keep you from smashing into a tree.</description>
		<content:encoded><![CDATA[<p>I&#8217;ll add to the nitpicking.  :p</p>
<p>Using Google as a calculator, and Nineplanets.org for dimensions:<br />
275 km/sec = 615157 mph<br />
Earth&#8217;s circumference = 24901 mi<br />
615157 / 24901 = 24.7 revolutions per hour<br />
1 hour / 24.7 = 146 seconds per revolution, not 90.  <img src='http://blogs.discovermagazine.com/badastronomy/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
<p>According to <a href="http://www.solstation.com/stars/vega.htm" rel="nofollow">http://www.solstation.com/stars/vega.htm</a>, the actual rotational period is 12.5 hours, which &#8220;suggest that the star is rotating at about 92 percent of the speed (angular velocity) that would cause it to physically fly apart&#8221;.</p>
<p>The orange &#8220;+&#8221; represents the &#8220;subsolar point&#8221;, according to the paper at the link Phil posted.  Doesn&#8217;t that mean a line between the core of Vega and us passes through that point?  Which in turn means it&#8217;s the center of the disc, as seen from here?</p>
<p>Finally, about the centripedal/centrifugal thing:  Not sure how it&#8217;s &#8220;officially&#8221; defined, but it seems logical to me to use them for the correct forces.  Since centripedal means &#8220;to the middle&#8221;, it should refer to the major body pulling inward on the minor body (whether major/minor be star/planet, planet CoG/planet particle, or person/bucket of water).  Since centrifugal means &#8220;away from the middle&#8221;, it should refer to the minor body pulling outward on the major body.  Both are real, opposite forces that are actually present in any reference frame.  The direction may seem to change (so which is which might be hard to define without a defined reference point), but they are still different forces.  The inertial effect is what gives the forces meaning (otherwise they&#8217;d both just instantly accelerate each other to infinity&#8211;or impact).</p>
<p>Like in a car: the centripedal force is the tires pulling the car towards the center of the corner, the centrifugal force is the car pushing the tires towards the edge of the road.  The inertial effect determines how much force the tires must overcome to keep you from smashing into a tree.</p>
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		<title>By: Blake Stacey</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13023</link>
		<dc:creator>Blake Stacey</dc:creator>
		<pubDate>Wed, 22 Mar 2006 20:29:09 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13023</guid>
		<description>After Einstein and Co. pointed out the importance of reference frames, back about a century ago, the way people talk about classical mechanics has gradually been changing.  The modern textbooks I&#039;m familiar with take the standpoint that when you pick a frame of reference, it comes with a set of forces.  The particular forces you use to describe an object (or multiple objects) in motion depend upon the reference frame you pick, and how your vantage point is moving relative to the bodies you&#039;re studying.

I haven&#039;t taken a classical mechanics class here in France, but since the physicists in this neck of academia seem to use the same concepts as those back in the United States, I expect they&#039;d think about &lt;i&gt;la force centripÃ¨te&lt;/i&gt; and &lt;i&gt;la force centrifuge&lt;/i&gt; the same way.

The details get horribly messy, and no two books describe rotating bodies in exactly the same way.  The &quot;centrifugal&quot; or &quot;centripetal&quot; forces are not the only things at work.  For example, imagine standing at the center of a merry-go-round and trying to walk to a point on the outer edge.  In a reference frame which rotates along with the carousel, a point on the edge is fixed with respect to the center:  walking from the center to the edge would look like a straight-line path.  But to a person standing outside the carousel, feet planted firmly on the ground, you would be moving in a spiral trajectory.

According to Newton&#039;s Laws, if a body in motion changes its speed or direction of movement, a force must be acting on it.  Joe, standing beside the carousel, sees Moe on the carousel changing his direction of motion, and so Joe deduces that a force must be acting on Moe, a &quot;Coriolis force&quot;.

Things can get even more fun when you consider motion on a spinning planet.  There are centripetal effects and Coriolis effects, and like I said, no two books want to talk about it the same way.  This is a ready source of problems used to torture college physics students:  &quot;A cannon at the North Pole fires a projectile at 500 meters per second.  If the planet were not rotating, the acceleration of gravity would be 9.8 meters per second squared, but the planet is rotating with an equitorial velocity of 1600 kilometers per hour.  Where will the cannonball hit the surface of the planet?&quot;

Really, too much brainpower has already been wasted arguing back and forth between &quot;centripetal&quot; and &quot;centrifugal&quot; this-or-that.  If demon gnomes snuck into all the libraries one night and swapped the two words everywhere they appear, it wouldn&#039;t make a difference.  (People who care about etymologies might get a little confused, but we already have plenty of words in science which go &quot;the wrong way&quot;:  &lt;i&gt;positive&lt;/i&gt; and &lt;i&gt;negative&lt;/i&gt; electric charge, for example.  &lt;i&gt;Cathode&lt;/i&gt; and &lt;i&gt;anode&lt;/i&gt; are also turned around, in consequence.)  We should be allowed to use whichever word we prefer when speaking in loose or qualitative terms, since everybody knows perfectly well what we&#039;re talking about.

The dispute over petals and fugals is the science-class equivalent of the arguments about splitting infinitives or ending sentences with prepositions.  It&#039;s all the sort of nonsense up with which we should not put.</description>
		<content:encoded><![CDATA[<p>After Einstein and Co. pointed out the importance of reference frames, back about a century ago, the way people talk about classical mechanics has gradually been changing.  The modern textbooks I&#8217;m familiar with take the standpoint that when you pick a frame of reference, it comes with a set of forces.  The particular forces you use to describe an object (or multiple objects) in motion depend upon the reference frame you pick, and how your vantage point is moving relative to the bodies you&#8217;re studying.</p>
<p>I haven&#8217;t taken a classical mechanics class here in France, but since the physicists in this neck of academia seem to use the same concepts as those back in the United States, I expect they&#8217;d think about <i>la force centripÃ¨te</i> and <i>la force centrifuge</i> the same way.</p>
<p>The details get horribly messy, and no two books describe rotating bodies in exactly the same way.  The &#8220;centrifugal&#8221; or &#8220;centripetal&#8221; forces are not the only things at work.  For example, imagine standing at the center of a merry-go-round and trying to walk to a point on the outer edge.  In a reference frame which rotates along with the carousel, a point on the edge is fixed with respect to the center:  walking from the center to the edge would look like a straight-line path.  But to a person standing outside the carousel, feet planted firmly on the ground, you would be moving in a spiral trajectory.</p>
<p>According to Newton&#8217;s Laws, if a body in motion changes its speed or direction of movement, a force must be acting on it.  Joe, standing beside the carousel, sees Moe on the carousel changing his direction of motion, and so Joe deduces that a force must be acting on Moe, a &#8220;Coriolis force&#8221;.</p>
<p>Things can get even more fun when you consider motion on a spinning planet.  There are centripetal effects and Coriolis effects, and like I said, no two books want to talk about it the same way.  This is a ready source of problems used to torture college physics students:  &#8220;A cannon at the North Pole fires a projectile at 500 meters per second.  If the planet were not rotating, the acceleration of gravity would be 9.8 meters per second squared, but the planet is rotating with an equitorial velocity of 1600 kilometers per hour.  Where will the cannonball hit the surface of the planet?&#8221;</p>
<p>Really, too much brainpower has already been wasted arguing back and forth between &#8220;centripetal&#8221; and &#8220;centrifugal&#8221; this-or-that.  If demon gnomes snuck into all the libraries one night and swapped the two words everywhere they appear, it wouldn&#8217;t make a difference.  (People who care about etymologies might get a little confused, but we already have plenty of words in science which go &#8220;the wrong way&#8221;:  <i>positive</i> and <i>negative</i> electric charge, for example.  <i>Cathode</i> and <i>anode</i> are also turned around, in consequence.)  We should be allowed to use whichever word we prefer when speaking in loose or qualitative terms, since everybody knows perfectly well what we&#8217;re talking about.</p>
<p>The dispute over petals and fugals is the science-class equivalent of the arguments about splitting infinitives or ending sentences with prepositions.  It&#8217;s all the sort of nonsense up with which we should not put.</p>
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		<title>By: Markk</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13022</link>
		<dc:creator>Markk</dc:creator>
		<pubDate>Wed, 22 Mar 2006 18:51:24 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13022</guid>
		<description>When you are inside a rotating reference frame, it feels like like something is pushing everything away radially, this is called &quot;centrifugal acceleration&quot;. When you are outside of the rotating reference frame looking at it it seems like there is a force holding the material in the reference frame from flying off in a straight line. This is the centripetal acceleration. They are the same thing as was said. I&#039;ll have to look at who coined the terms but I halfway remember it was Laplace or somebody like that, so I actually think this distinction is also made in France Jean-Denis, could be mis-remembering though.</description>
		<content:encoded><![CDATA[<p>When you are inside a rotating reference frame, it feels like like something is pushing everything away radially, this is called &#8220;centrifugal acceleration&#8221;. When you are outside of the rotating reference frame looking at it it seems like there is a force holding the material in the reference frame from flying off in a straight line. This is the centripetal acceleration. They are the same thing as was said. I&#8217;ll have to look at who coined the terms but I halfway remember it was Laplace or somebody like that, so I actually think this distinction is also made in France Jean-Denis, could be mis-remembering though.</p>
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		<title>By: The Bad Astronomer</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13021</link>
		<dc:creator>The Bad Astronomer</dc:creator>
		<pubDate>Wed, 22 Mar 2006 18:06:13 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13021</guid>
		<description>In stars, blue is hotter and red is cooler. I wondered if someone would ask about that...</description>
		<content:encoded><![CDATA[<p>In stars, blue is hotter and red is cooler. I wondered if someone would ask about that&#8230;</p>
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		<title>By: Kevin Grant</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13020</link>
		<dc:creator>Kevin Grant</dc:creator>
		<pubDate>Wed, 22 Mar 2006 18:01:47 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13020</guid>
		<description>Phil,

College physics was a long time ago for me. In an example of a child spinning a rock on a string, I distinctly recall that centripetal force was the force keeping the rock on the string from flying away--ie it was the force exerted on the rock by the string. That&#039;s the opposite of centrifugal force, which is the force pushing the rock away from the child.</description>
		<content:encoded><![CDATA[<p>Phil,</p>
<p>College physics was a long time ago for me. In an example of a child spinning a rock on a string, I distinctly recall that centripetal force was the force keeping the rock on the string from flying away&#8211;ie it was the force exerted on the rock by the string. That&#8217;s the opposite of centrifugal force, which is the force pushing the rock away from the child.</p>
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		<title>By: Jean-Denis</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/comment-page-1/#comment-13019</link>
		<dc:creator>Jean-Denis</dc:creator>
		<pubDate>Wed, 22 Mar 2006 17:42:45 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2006/03/21/giving-vega-a-spin/#comment-13019</guid>
		<description>&quot;Centripetal&quot; and &quot;centrifugal&quot; as words having opposite meanings (at least in common French, and from etymology), if they designate the same force, then I feel it is very much lacking in clarity. I am glad I attended my physics classes in French: there was no room for confusion in the vocabulary ;-)</description>
		<content:encoded><![CDATA[<p>&#8220;Centripetal&#8221; and &#8220;centrifugal&#8221; as words having opposite meanings (at least in common French, and from etymology), if they designate the same force, then I feel it is very much lacking in clarity. I am glad I attended my physics classes in French: there was no room for confusion in the vocabulary <img src='http://blogs.discovermagazine.com/badastronomy/wp-includes/images/smilies/icon_wink.gif' alt=';-)' class='wp-smiley' /> </p>
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