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	<title>Comments on: epi &#8211; pi</title>
	<atom:link href="http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/feed/" rel="self" type="application/rss+xml" />
	<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/</link>
	<description>I am an astronomer, writer, and skeptic. I likes reality the way it is, and I aims to keep it that way. My real name is Phil Plait, and I run the Bad Astronomy blog.</description>
	<lastBuildDate>Mon, 13 Feb 2012 15:55:58 +0000</lastBuildDate>
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		<title>By: Gerson W. Barbosa</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-2/#comment-315792</link>
		<dc:creator>Gerson W. Barbosa</dc:creator>
		<pubDate>Wed, 06 Oct 2010 20:00:03 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-315792</guid>
		<description>I&#039;ve come up with a slightly more weird expression:

 (sqrt(2)*(pi^17-4*e^pi*(e^pi-pi)))/4 = 99999999.979

I guess this would have worked in the XKCD comic as well :-)</description>
		<content:encoded><![CDATA[<p>I&#8217;ve come up with a slightly more weird expression:</p>
<p> (sqrt(2)*(pi^17-4*e^pi*(e^pi-pi)))/4 = 99999999.979</p>
<p>I guess this would have worked in the XKCD comic as well <img src='http://blogs.discovermagazine.com/badastronomy/wp-includes/images/smilies/icon_smile.gif' alt=':-)' class='wp-smiley' /> </p>
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		<title>By: Julie</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-2/#comment-282340</link>
		<dc:creator>Julie</dc:creator>
		<pubDate>Tue, 13 Jul 2010 17:07:05 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-282340</guid>
		<description>&quot;Hey, no one’s mentioned the alt-text in that XKCD comic yet:

“Also, I hear the 4th root of (9^2 + 19^2/22) is pi.”

Someone with Mathematica try that out.&quot;

Why the hell would you need mathematica to do that? Put it in a calculator or use Google calculator.</description>
		<content:encoded><![CDATA[<p>&#8220;Hey, no one’s mentioned the alt-text in that XKCD comic yet:</p>
<p>“Also, I hear the 4th root of (9^2 + 19^2/22) is pi.”</p>
<p>Someone with Mathematica try that out.&#8221;</p>
<p>Why the hell would you need mathematica to do that? Put it in a calculator or use Google calculator.</p>
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		<title>By: Bas Joosten</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-2/#comment-224368</link>
		<dc:creator>Bas Joosten</dc:creator>
		<pubDate>Wed, 04 Nov 2009 12:47:56 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-224368</guid>
		<description>In reply to Adam:
“Also, I hear the 4th root of (9^2 + 19^2/22) is pi.”
I have no mathematica, but I can do high precision calculations. Found out it is approximately pi up to the 9th digit. Aproximately equal is still unequal, of course.</description>
		<content:encoded><![CDATA[<p>In reply to Adam:<br />
“Also, I hear the 4th root of (9^2 + 19^2/22) is pi.”<br />
I have no mathematica, but I can do high precision calculations. Found out it is approximately pi up to the 9th digit. Aproximately equal is still unequal, of course.</p>
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		<title>By: ElBosso</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-2/#comment-219419</link>
		<dc:creator>ElBosso</dc:creator>
		<pubDate>Mon, 12 Oct 2009 18:43:16 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-219419</guid>
		<description>1111,1111^2 = 1234567,87654       &#124;*7,2
                          = 8888888,71109       &#124;sqrt (4 times)
                          = 2,718335  -&gt; nearly e^1 !
cool, isn´t it?
found out by myself!</description>
		<content:encoded><![CDATA[<p>1111,1111^2 = 1234567,87654       |*7,2<br />
                          = 8888888,71109       |sqrt (4 times)<br />
                          = 2,718335  -> nearly e^1 !<br />
cool, isn´t it?<br />
found out by myself!</p>
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		<title>By: Eikinkloster</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-2/#comment-208664</link>
		<dc:creator>Eikinkloster</dc:creator>
		<pubDate>Tue, 25 Aug 2009 17:46:53 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-208664</guid>
		<description>For those who are pissed because they don&#039;t get the whole fuss:

1) Click on the image. It will take you to the actual comic. The image is only the first of three frames.
2)  The joke in a nutshell: e^pi - pi = 19.999099979, which is very very close to 20. So close that if you don&#039;t know better, you&#039;ll feel tempted to believe you&#039;ve introduced some rounding error on the calculation. The math guy exploits this to drive the computer guys from ACM nuts trying to find where they were making the mistake.</description>
		<content:encoded><![CDATA[<p>For those who are pissed because they don&#8217;t get the whole fuss:</p>
<p>1) Click on the image. It will take you to the actual comic. The image is only the first of three frames.<br />
2)  The joke in a nutshell: e^pi &#8211; pi = 19.999099979, which is very very close to 20. So close that if you don&#8217;t know better, you&#8217;ll feel tempted to believe you&#8217;ve introduced some rounding error on the calculation. The math guy exploits this to drive the computer guys from ACM nuts trying to find where they were making the mistake.</p>
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		<title>By: adam</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-201811</link>
		<dc:creator>adam</dc:creator>
		<pubDate>Fri, 24 Jul 2009 16:56:43 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-201811</guid>
		<description>Hey, no one&#039;s mentioned the alt-text in that XKCD comic yet:

&quot;Also, I hear the 4th root of (9^2 + 19^2/22) is pi.&quot;

Someone with Mathematica try that out.</description>
		<content:encoded><![CDATA[<p>Hey, no one&#8217;s mentioned the alt-text in that XKCD comic yet:</p>
<p>&#8220;Also, I hear the 4th root of (9^2 + 19^2/22) is pi.&#8221;</p>
<p>Someone with Mathematica try that out.</p>
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		<title>By: Steven</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-159806</link>
		<dc:creator>Steven</dc:creator>
		<pubDate>Tue, 03 Mar 2009 08:07:09 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-159806</guid>
		<description>http://mathworld.wolfram.com/AlmostInteger.html</description>
		<content:encoded><![CDATA[<p><a href="http://mathworld.wolfram.com/AlmostInteger.html" rel="nofollow">http://mathworld.wolfram.com/AlmostInteger.html</a></p>
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		<title>By: Action Lyrics</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-157201</link>
		<dc:creator>Action Lyrics</dc:creator>
		<pubDate>Wed, 18 Feb 2009 05:43:36 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-157201</guid>
		<description>I agree with you, I think it&#039;s just a coincidence.

There are plenty of them if u look for them.

Eg sqrt(10) approx = 22/7 approx = pi.

Even though none of those are integers.</description>
		<content:encoded><![CDATA[<p>I agree with you, I think it&#8217;s just a coincidence.</p>
<p>There are plenty of them if u look for them.</p>
<p>Eg sqrt(10) approx = 22/7 approx = pi.</p>
<p>Even though none of those are integers.</p>
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		<title>By: Patrick</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-128134</link>
		<dc:creator>Patrick</dc:creator>
		<pubDate>Fri, 24 Oct 2008 18:31:50 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-128134</guid>
		<description>The most explicit definition of e is e = 1 + 1/1! + 1/2! + 1/3! + ...

This is a rapidly converging sum (remember n! = n times (n-1) times ... times 1).</description>
		<content:encoded><![CDATA[<p>The most explicit definition of e is e = 1 + 1/1! + 1/2! + 1/3! + &#8230;</p>
<p>This is a rapidly converging sum (remember n! = n times (n-1) times &#8230; times 1).</p>
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		<title>By: Sephiroth</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28889</link>
		<dc:creator>Sephiroth</dc:creator>
		<pubDate>Mon, 17 Dec 2007 16:03:25 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28889</guid>
		<description>e=the tangent line of f(x)=e^x where x=0</description>
		<content:encoded><![CDATA[<p>e=the tangent line of f(x)=e^x where x=0</p>
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		<title>By: Some other guy</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28888</link>
		<dc:creator>Some other guy</dc:creator>
		<pubDate>Wed, 12 Sep 2007 03:24:34 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28888</guid>
		<description>Does anyone know the official definition of &quot;e&quot;?

I know one fact, that if you tetrate (see http://en.wikipedia.org/wiki/Tetration) e-rt(e) (The base-e root of e) to infinity, the result is e, but if you tetrate anything higher than that to infinity, be it just 10^-1000000000 higher, it goes to infinity. (Well, I actually found this out from experimentation.)</description>
		<content:encoded><![CDATA[<p>Does anyone know the official definition of &#8220;e&#8221;?</p>
<p>I know one fact, that if you tetrate (see <a href="http://en.wikipedia.org/wiki/Tetration" rel="nofollow">http://en.wikipedia.org/wiki/Tetration</a>) e-rt(e) (The base-e root of e) to infinity, the result is e, but if you tetrate anything higher than that to infinity, be it just 10^-1000000000 higher, it goes to infinity. (Well, I actually found this out from experimentation.)</p>
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		<title>By: Brian</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28887</link>
		<dc:creator>Brian</dc:creator>
		<pubDate>Tue, 13 Feb 2007 22:09:53 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28887</guid>
		<description>e[sup]pi&gt;pi[sup]e</description>
		<content:encoded><![CDATA[<p>e[sup]pi&gt;pi[sup]e</p>
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		<title>By: Brian</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28886</link>
		<dc:creator>Brian</dc:creator>
		<pubDate>Sun, 11 Feb 2007 20:22:09 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28886</guid>
		<description>Thanx all for some very interesting posts.  In response to Samuel&#039;s hint of a deeper reason that e^pi &gt; pi^e, let f(x) = ln(x)/x.  Then f&#039;(x)=(1-ln(x))/(x^2).
f&#039;(x)=0 if and only if x=e, which yields a maximum at x=e for all positive values of x.  So if A&gt;0 and A not equal to e, f(e)&gt;f(A)
                                                  ln(e)/e&gt;ln(A)/A
                                                   Aln(e)&gt;eln(A)
                                                 ln(e^A)&gt;ln(A^e)
                                                      e^A&gt;A^e
e^pi&gt;pi^e is a special case.</description>
		<content:encoded><![CDATA[<p>Thanx all for some very interesting posts.  In response to Samuel&#8217;s hint of a deeper reason that e^pi &gt; pi^e, let f(x) = ln(x)/x.  Then f&#8217;(x)=(1-ln(x))/(x^2).<br />
f&#8217;(x)=0 if and only if x=e, which yields a maximum at x=e for all positive values of x.  So if A&gt;0 and A not equal to e, f(e)&gt;f(A)<br />
                                                  ln(e)/e&gt;ln(A)/A<br />
                                                   Aln(e)&gt;eln(A)<br />
                                                 ln(e^A)&gt;ln(A^e)<br />
                                                      e^A&gt;A^e<br />
e^pi&gt;pi^e is a special case.</p>
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		<title>By: Steve</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28885</link>
		<dc:creator>Steve</dc:creator>
		<pubDate>Fri, 02 Feb 2007 10:51:57 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28885</guid>
		<description>Phill you B*$*Â£&quot;%  Hadn&#039;t been aware of that webcomic before, thanks for giving me another way to waste time at work (as if i didn&#039;t have enough already) :)</description>
		<content:encoded><![CDATA[<p>Phill you B*$*Â£&#8221;%  Hadn&#8217;t been aware of that webcomic before, thanks for giving me another way to waste time at work (as if i didn&#8217;t have enough already) <img src='http://blogs.discovermagazine.com/badastronomy/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
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		<title>By: Patrick</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28884</link>
		<dc:creator>Patrick</dc:creator>
		<pubDate>Thu, 01 Feb 2007 21:39:23 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28884</guid>
		<description>Phil is commenting on the fact that the result is near 20, but that&#039;s not the end of joke. Read the rest of the comic!</description>
		<content:encoded><![CDATA[<p>Phil is commenting on the fact that the result is near 20, but that&#8217;s not the end of joke. Read the rest of the comic!</p>
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		<title>By: Bill Nettles</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28883</link>
		<dc:creator>Bill Nettles</dc:creator>
		<pubDate>Thu, 01 Feb 2007 20:35:49 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28883</guid>
		<description>Correction:
In Si units, the acceleration of gravity near the surface of the earth is very close to pi^2.  Hmmmm.  [I SQRT&#039;d the wrong thing...that can be dangerous]</description>
		<content:encoded><![CDATA[<p>Correction:<br />
In Si units, the acceleration of gravity near the surface of the earth is very close to pi^2.  Hmmmm.  [I SQRT'd the wrong thing...that can be dangerous]</p>
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		<title>By: Bill Nettles</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28882</link>
		<dc:creator>Bill Nettles</dc:creator>
		<pubDate>Thu, 01 Feb 2007 20:33:19 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28882</guid>
		<description>Physics has interesting numerical coincidences which suggest that our standard measurements need tweaking:

The number of seconds in a tropical year is about 3.1557 x 10^7 seconds, remarkably close to pi x 10^7.  If the second was just a little &quot;longer&quot;, then they would match, as long as the earth doesn&#039;t slow down.

In SI units, the acceleration of gravity near the surface of the earth is very close to the SQRT(pi). Hmmmm...

Finally, we know where Ol&#039; McDonalds Farm is: on the Argand Plain [sic] about 0.6517 units from the origin (wherever THAT is), 38.22 degress east of south.  Check out e^(i^(e^(i^0))).  Oh, and the imaginary component of the farm has a magnitude close to (slightly larger than) the mass-energy of the electron in MeV. Ooooo...</description>
		<content:encoded><![CDATA[<p>Physics has interesting numerical coincidences which suggest that our standard measurements need tweaking:</p>
<p>The number of seconds in a tropical year is about 3.1557 x 10^7 seconds, remarkably close to pi x 10^7.  If the second was just a little &#8220;longer&#8221;, then they would match, as long as the earth doesn&#8217;t slow down.</p>
<p>In SI units, the acceleration of gravity near the surface of the earth is very close to the SQRT(pi). Hmmmm&#8230;</p>
<p>Finally, we know where Ol&#8217; McDonalds Farm is: on the Argand Plain [sic] about 0.6517 units from the origin (wherever THAT is), 38.22 degress east of south.  Check out e^(i^(e^(i^0))).  Oh, and the imaginary component of the farm has a magnitude close to (slightly larger than) the mass-energy of the electron in MeV. Ooooo&#8230;</p>
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		<title>By: Quiet_Desperation</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28881</link>
		<dc:creator>Quiet_Desperation</dc:creator>
		<pubDate>Thu, 01 Feb 2007 19:47:04 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28881</guid>
		<description>I used to like math humor until my uncle was killed in a tragic long division accident.</description>
		<content:encoded><![CDATA[<p>I used to like math humor until my uncle was killed in a tragic long division accident.</p>
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		<title>By: Rob</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28880</link>
		<dc:creator>Rob</dc:creator>
		<pubDate>Thu, 01 Feb 2007 19:42:21 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28880</guid>
		<description>Sweet Lord Christ, could someone please explain what the $%*k this means to those of us who don&#039;t get it?

Maybe we should just accept that we&#039;re out of our league and leave you Matharians to enjoy yourselves, but I feel I&#039;m smart enough to play with you guys if you&#039;ll help me understand.

Thanks
Rob</description>
		<content:encoded><![CDATA[<p>Sweet Lord Christ, could someone please explain what the $%*k this means to those of us who don&#8217;t get it?</p>
<p>Maybe we should just accept that we&#8217;re out of our league and leave you Matharians to enjoy yourselves, but I feel I&#8217;m smart enough to play with you guys if you&#8217;ll help me understand.</p>
<p>Thanks<br />
Rob</p>
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		<title>By: Todd</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28879</link>
		<dc:creator>Todd</dc:creator>
		<pubDate>Thu, 01 Feb 2007 19:13:47 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28879</guid>
		<description>It&#039;s a coincidence.

Kind of like the coincidence that

10! (=10*9*8*...*3*2*1) is exactly equal to the number of seconds in 6 weeks.

Given that there are an infinite number of numbers, coincidences can always be found.</description>
		<content:encoded><![CDATA[<p>It&#8217;s a coincidence.</p>
<p>Kind of like the coincidence that</p>
<p>10! (=10*9*8*&#8230;*3*2*1) is exactly equal to the number of seconds in 6 weeks.</p>
<p>Given that there are an infinite number of numbers, coincidences can always be found.</p>
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		<title>By: APP</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28878</link>
		<dc:creator>APP</dc:creator>
		<pubDate>Thu, 01 Feb 2007 18:12:54 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28878</guid>
		<description>&lt;i&gt;Pi itself is much more interesting in the first 10 digits you get all 10 digits. Of course this is in the base 10 number system which only appeals to us because we have 10 fingers.&lt;/i&gt;

Huh?

3.141592653...

Two 1&#039;s, two 3&#039;s, two 5&#039;s, no 0&#039;s, 7&#039;s, or 8&#039;s.</description>
		<content:encoded><![CDATA[<p><i>Pi itself is much more interesting in the first 10 digits you get all 10 digits. Of course this is in the base 10 number system which only appeals to us because we have 10 fingers.</i></p>
<p>Huh?</p>
<p>3.141592653&#8230;</p>
<p>Two 1&#8242;s, two 3&#8242;s, two 5&#8242;s, no 0&#8242;s, 7&#8242;s, or 8&#8242;s.</p>
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		<title>By: DennyMo</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28877</link>
		<dc:creator>DennyMo</dc:creator>
		<pubDate>Thu, 01 Feb 2007 14:26:59 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28877</guid>
		<description>I was gonna make some pithy comment about those stupid emails that have you go through some silly math gymnastics and arrive at some result that sounds impressive or surprising.  But then you all start throwing around imaginary numbers, natural logarithms, etc., makes my comment seem kinda sophomoric, so I&#039;m gonna just keep my mouth shut...</description>
		<content:encoded><![CDATA[<p>I was gonna make some pithy comment about those stupid emails that have you go through some silly math gymnastics and arrive at some result that sounds impressive or surprising.  But then you all start throwing around imaginary numbers, natural logarithms, etc., makes my comment seem kinda sophomoric, so I&#8217;m gonna just keep my mouth shut&#8230;</p>
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		<title>By: AntiQuest</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28876</link>
		<dc:creator>AntiQuest</dc:creator>
		<pubDate>Thu, 01 Feb 2007 14:25:46 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28876</guid>
		<description>I (physics student) caught out a few of the Comp Sci majors with this today. Not really significant but funny to see them struggle with thier program.

Oh and TomPaine, check out Tom Lehrer before you say mathematicians aren&#039;t funny. Especially &quot;That&#039;s mathematics&quot; (and &quot;Werner von Braun&quot; for the Phil&#039;s interest...).</description>
		<content:encoded><![CDATA[<p>I (physics student) caught out a few of the Comp Sci majors with this today. Not really significant but funny to see them struggle with thier program.</p>
<p>Oh and TomPaine, check out Tom Lehrer before you say mathematicians aren&#8217;t funny. Especially &#8220;That&#8217;s mathematics&#8221; (and &#8220;Werner von Braun&#8221; for the Phil&#8217;s interest&#8230;).</p>
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		<title>By: Kullat Nunu</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28875</link>
		<dc:creator>Kullat Nunu</dc:creator>
		<pubDate>Thu, 01 Feb 2007 10:13:15 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28875</guid>
		<description>My favorite is

e^(i * pi) + 1 = 0

Three basic arithmetic functions (+, *, ^), five fundamental constants (0, 1, pi, e, i [= imaginary unit, i^2 = -1]), one equation.

And it is not  a coincidence.

Ah, &lt;b&gt;Dr. Goulu&lt;/b&gt; already mentioned it.</description>
		<content:encoded><![CDATA[<p>My favorite is</p>
<p>e^(i * pi) + 1 = 0</p>
<p>Three basic arithmetic functions (+, *, ^), five fundamental constants (0, 1, pi, e, i [= imaginary unit, i^2 = -1]), one equation.</p>
<p>And it is not  a coincidence.</p>
<p>Ah, <b>Dr. Goulu</b> already mentioned it.</p>
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		<title>By: Lab Lemming</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/comment-page-1/#comment-28874</link>
		<dc:creator>Lab Lemming</dc:creator>
		<pubDate>Thu, 01 Feb 2007 08:55:00 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28874</guid>
		<description>Some numerical coincidences are useful!

When I took geophysics, we would cancel out the pi that results from the earth&#039;s orbit in various geophysical calculations by approximating a year as pi x 10^7 seconds.  Obviously you don&#039;t want the guys who do spacecraft trajectories using this trick, but it&#039;s close enough for the order-of-magnitude type calculations that we did in undergrad planetary.</description>
		<content:encoded><![CDATA[<p>Some numerical coincidences are useful!</p>
<p>When I took geophysics, we would cancel out the pi that results from the earth&#8217;s orbit in various geophysical calculations by approximating a year as pi x 10^7 seconds.  Obviously you don&#8217;t want the guys who do spacecraft trajectories using this trick, but it&#8217;s close enough for the order-of-magnitude type calculations that we did in undergrad planetary.</p>
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