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	<title>Comments on: epi - pi</title>
	<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/</link>
	<description>I am an astronomer, writer, and skeptic. I likes reality the way it is, and I aims to keep it that way. My real name is Phil Plait, and I run the Bad Astronomy blog.</description>
	<pubDate>Sat, 10 Jan 2009 02:22:18 +0000</pubDate>
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		<title>By: Patrick</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-128134</link>
		<dc:creator>Patrick</dc:creator>
		<pubDate>Fri, 24 Oct 2008 18:31:50 +0000</pubDate>
		<guid>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-128134</guid>
		<description>The most explicit definition of e is e = 1 + 1/1! + 1/2! + 1/3! + ...

This is a rapidly converging sum (remember n! = n times (n-1) times ... times 1).</description>
		<content:encoded><![CDATA[<p>The most explicit definition of e is e = 1 + 1/1! + 1/2! + 1/3! + &#8230;</p>
<p>This is a rapidly converging sum (remember n! = n times (n-1) times &#8230; times 1).</p>
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		<title>By: Sephiroth</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28889</link>
		<dc:creator>Sephiroth</dc:creator>
		<pubDate>Mon, 17 Dec 2007 16:03:25 +0000</pubDate>
		<guid>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28889</guid>
		<description>e=the tangent line of f(x)=e^x where x=0</description>
		<content:encoded><![CDATA[<p>e=the tangent line of f(x)=e^x where x=0</p>
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		<title>By: Some other guy</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28888</link>
		<dc:creator>Some other guy</dc:creator>
		<pubDate>Wed, 12 Sep 2007 03:24:34 +0000</pubDate>
		<guid>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28888</guid>
		<description>Does anyone know the official definition of "e"?

I know one fact, that if you tetrate (see http://en.wikipedia.org/wiki/Tetration) e-rt(e) (The base-e root of e) to infinity, the result is e, but if you tetrate anything higher than that to infinity, be it just 10^-1000000000 higher, it goes to infinity. (Well, I actually found this out from experimentation.)</description>
		<content:encoded><![CDATA[<p>Does anyone know the official definition of &#8220;e&#8221;?</p>
<p>I know one fact, that if you tetrate (see <a href="http://en.wikipedia.org/wiki/Tetration" rel="nofollow">http://en.wikipedia.org/wiki/Tetration</a>) e-rt(e) (The base-e root of e) to infinity, the result is e, but if you tetrate anything higher than that to infinity, be it just 10^-1000000000 higher, it goes to infinity. (Well, I actually found this out from experimentation.)</p>
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		<title>By: Brian</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28887</link>
		<dc:creator>Brian</dc:creator>
		<pubDate>Tue, 13 Feb 2007 22:09:53 +0000</pubDate>
		<guid>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28887</guid>
		<description>e[sup]pi&#62;pi[sup]e</description>
		<content:encoded><![CDATA[<p>e[sup]pi&gt;pi[sup]e</p>
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		<title>By: Brian</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28886</link>
		<dc:creator>Brian</dc:creator>
		<pubDate>Sun, 11 Feb 2007 20:22:09 +0000</pubDate>
		<guid>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28886</guid>
		<description>Thanx all for some very interesting posts.  In response to Samuel's hint of a deeper reason that e^pi &#62; pi^e, let f(x) = ln(x)/x.  Then f'(x)=(1-ln(x))/(x^2).
f'(x)=0 if and only if x=e, which yields a maximum at x=e for all positive values of x.  So if A&#62;0 and A not equal to e, f(e)&#62;f(A)
                                                  ln(e)/e&#62;ln(A)/A
                                                   Aln(e)&#62;eln(A)
                                                 ln(e^A)&#62;ln(A^e)
                                                      e^A&#62;A^e
e^pi&#62;pi^e is a special case.</description>
		<content:encoded><![CDATA[<p>Thanx all for some very interesting posts.  In response to Samuel&#8217;s hint of a deeper reason that e^pi &gt; pi^e, let f(x) = ln(x)/x.  Then f&#8217;(x)=(1-ln(x))/(x^2).<br />
f&#8217;(x)=0 if and only if x=e, which yields a maximum at x=e for all positive values of x.  So if A&gt;0 and A not equal to e, f(e)&gt;f(A)<br />
                                                  ln(e)/e&gt;ln(A)/A<br />
                                                   Aln(e)&gt;eln(A)<br />
                                                 ln(e^A)&gt;ln(A^e)<br />
                                                      e^A&gt;A^e<br />
e^pi&gt;pi^e is a special case.</p>
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		<title>By: Steve</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28885</link>
		<dc:creator>Steve</dc:creator>
		<pubDate>Fri, 02 Feb 2007 10:51:57 +0000</pubDate>
		<guid>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28885</guid>
		<description>Phill you B*$*Â£"%  Hadn't been aware of that webcomic before, thanks for giving me another way to waste time at work (as if i didn't have enough already) :)</description>
		<content:encoded><![CDATA[<p>Phill you B*$*Â£&#8221;%  Hadn&#8217;t been aware of that webcomic before, thanks for giving me another way to waste time at work (as if i didn&#8217;t have enough already) <img src='http://blogs.discovermagazine.com/badastronomy/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /></p>
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		<title>By: Patrick</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28884</link>
		<dc:creator>Patrick</dc:creator>
		<pubDate>Thu, 01 Feb 2007 21:39:23 +0000</pubDate>
		<guid>http://blogs.discovermagazine.com/badastronomy/2007/01/31/epi-pi/#comment-28884</guid>
		<description>Phil is commenting on the fact that the result is near 20, but that's not the end of joke. Read the rest of the comic!</description>
		<content:encoded><![CDATA[<p>Phil is commenting on the fact that the result is near 20, but that&#8217;s not the end of joke. Read the rest of the comic!</p>
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