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	<title>Comments on: MESSENGER: Three days out from Mercury</title>
	<atom:link href="http://blogs.discovermagazine.com/badastronomy/2009/09/27/messenger-three-days-out-from-mercury/feed/" rel="self" type="application/rss+xml" />
	<link>http://blogs.discovermagazine.com/badastronomy/2009/09/27/messenger-three-days-out-from-mercury/</link>
	<description>I am an astronomer, writer, and skeptic. I likes reality the way it is, and I aims to keep it that way. My real name is Phil Plait, and I run the Bad Astronomy blog.</description>
	<lastBuildDate>Sun, 22 Nov 2009 20:11:43 -0600</lastBuildDate>
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		<title>By: Asimov Fan</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2009/09/27/messenger-three-days-out-from-mercury/comment-page-1/#comment-216698</link>
		<dc:creator>Asimov Fan</dc:creator>
		<pubDate>Wed, 30 Sep 2009 06:33:06 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/?p=5587#comment-216698</guid>
		<description>@ 24. Troy - Thanks. :-)

@ 17.   Neil Haggath Says: 

&lt;i&gt;A challenge to astrologers… They say Mercury will “enter Libra” on 10 October. So… I will personally give one million dollars to any astrologer who can photograph Mercury, on 11 October, among the stars of the constellation Libra. Of course, I don’t have a million dollars, but I don’t think I need to worry! &lt;/i&gt;

Be careful there - there&#039;s always photoshop! ;-) 

You&#039;d be well advised to stress a &lt;b&gt;genuine, unfaked and confirmed&lt;/b&gt; photo. Then agian I wonder how many astrologers could even find Libra in the sky or name any of its stars and their spectral types. ;-)</description>
		<content:encoded><![CDATA[<p>@ 24. Troy &#8211; Thanks. <img src='http://blogs.discovermagazine.com/badastronomy/wp-includes/images/smilies/icon_smile.gif' alt=':-)' class='wp-smiley' /> </p>
<p>@ 17.   Neil Haggath Says: </p>
<p><i>A challenge to astrologers… They say Mercury will “enter Libra” on 10 October. So… I will personally give one million dollars to any astrologer who can photograph Mercury, on 11 October, among the stars of the constellation Libra. Of course, I don’t have a million dollars, but I don’t think I need to worry! </i></p>
<p>Be careful there &#8211; there&#8217;s always photoshop! <img src='http://blogs.discovermagazine.com/badastronomy/wp-includes/images/smilies/icon_wink.gif' alt=';-)' class='wp-smiley' />  </p>
<p>You&#8217;d be well advised to stress a <b>genuine, unfaked and confirmed</b> photo. Then agian I wonder how many astrologers could even find Libra in the sky or name any of its stars and their spectral types. <img src='http://blogs.discovermagazine.com/badastronomy/wp-includes/images/smilies/icon_wink.gif' alt=';-)' class='wp-smiley' /> </p>
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		<title>By: Gary Ansorge</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2009/09/27/messenger-three-days-out-from-mercury/comment-page-1/#comment-216360</link>
		<dc:creator>Gary Ansorge</dc:creator>
		<pubDate>Tue, 29 Sep 2009 00:19:40 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/?p=5587#comment-216360</guid>
		<description>23. Bryan Feir

That&#039;s actually a much better description of orbital ballistics than Heinliens, since the closer you are to the sun, the faster you have to move in order to remain in orbit but it&#039;s also true that to drop your orbit closer to the sun you have to slow down from current velocity. The thing is, as your orbit decays(gets closer to the sun) your velocity WILL increase. It&#039;s much more about ones potential energy(height above the gravity source times mass times the acceleration) being converted to kinetic energy(velocity^2  times mass/2). We start at a high potential energy with some kinetic energy,ie,earths velocity is about 30 km/sec and we&#039;re about 150 million km above the sun, so we have both potential and kinetic energy. That&#039;s what makes it so darned counter intuitive to figure out how to go where we want to go. To get closer to the sun, we reduce our orbital velocity, drop down and our Velocity then increases while potential energy decreases.  If you twirl a weight around on a string, pull it in closer to you(pretend you&#039;re the sun) it will increase the objects velocity. If you reduce the velocity, it&#039;s distance from you will decrease. Not the greatest model, because it&#039;s also affected by earths gravity but maybe it will give some insight.
Jus an addendum: Mercurys velocity is about 48 km/sec.

GAry 7</description>
		<content:encoded><![CDATA[<p>23. Bryan Feir</p>
<p>That&#8217;s actually a much better description of orbital ballistics than Heinliens, since the closer you are to the sun, the faster you have to move in order to remain in orbit but it&#8217;s also true that to drop your orbit closer to the sun you have to slow down from current velocity. The thing is, as your orbit decays(gets closer to the sun) your velocity WILL increase. It&#8217;s much more about ones potential energy(height above the gravity source times mass times the acceleration) being converted to kinetic energy(velocity^2  times mass/2). We start at a high potential energy with some kinetic energy,ie,earths velocity is about 30 km/sec and we&#8217;re about 150 million km above the sun, so we have both potential and kinetic energy. That&#8217;s what makes it so darned counter intuitive to figure out how to go where we want to go. To get closer to the sun, we reduce our orbital velocity, drop down and our Velocity then increases while potential energy decreases.  If you twirl a weight around on a string, pull it in closer to you(pretend you&#8217;re the sun) it will increase the objects velocity. If you reduce the velocity, it&#8217;s distance from you will decrease. Not the greatest model, because it&#8217;s also affected by earths gravity but maybe it will give some insight.<br />
Jus an addendum: Mercurys velocity is about 48 km/sec.</p>
<p>GAry 7</p>
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		<title>By: Troy</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2009/09/27/messenger-three-days-out-from-mercury/comment-page-1/#comment-216359</link>
		<dc:creator>Troy</dc:creator>
		<pubDate>Tue, 29 Sep 2009 00:07:01 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/?p=5587#comment-216359</guid>
		<description>Asimov fan, yes there are probably small parts not imaged.</description>
		<content:encoded><![CDATA[<p>Asimov fan, yes there are probably small parts not imaged.</p>
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		<title>By: Bryan Feir</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2009/09/27/messenger-three-days-out-from-mercury/comment-page-1/#comment-216333</link>
		<dc:creator>Bryan Feir</dc:creator>
		<pubDate>Mon, 28 Sep 2009 22:31:35 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/?p=5587#comment-216333</guid>
		<description>Wayne @#12:

Or, as one of my physics profs used to say, in orbital mechanics you have to go forward to go up, go up to go back, go back to go down, and go down to go forward.

(Forward to go up: forward acceleration shifts you into a higher orbit.  Up to go back: going straight up causes you to lose angular velocity because you have greater distance per orbit.  Back to go down: reverse acceleration causes your orbit to decay.  And down to go forward, dropping down increases your angular velocity because the orbit is smaller but your linear velocity stays similar.)

Real-time orbital corrections can be highly non-intuitive.</description>
		<content:encoded><![CDATA[<p>Wayne @#12:</p>
<p>Or, as one of my physics profs used to say, in orbital mechanics you have to go forward to go up, go up to go back, go back to go down, and go down to go forward.</p>
<p>(Forward to go up: forward acceleration shifts you into a higher orbit.  Up to go back: going straight up causes you to lose angular velocity because you have greater distance per orbit.  Back to go down: reverse acceleration causes your orbit to decay.  And down to go forward, dropping down increases your angular velocity because the orbit is smaller but your linear velocity stays similar.)</p>
<p>Real-time orbital corrections can be highly non-intuitive.</p>
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		<title>By: Torbjörn Larsson, OM</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2009/09/27/messenger-three-days-out-from-mercury/comment-page-1/#comment-216324</link>
		<dc:creator>Torbjörn Larsson, OM</dc:creator>
		<pubDate>Mon, 28 Sep 2009 21:36:29 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.discovermagazine.com/badastronomy/?p=5587#comment-216324</guid>
		<description>#12 Wayne, 

Thanks for the kind words, but truth is I messed up big time as I glossed over the potential energy loss before acquiring the orbit. Luckily toasterhead listened to saner advice.

I like your argument, because then I don&#039;t need to analyze orbital motion for its effect on energy balance. 

Yet another way to see that a round orbit is the least energy state is to realize that this is the reason for hydrostatic spherical shape of planets. [More generally, this condition must mean stability of this type of field, or, say, planets would split and sunder.] So the probe going in another trajectory at the moment it hits Mercury orbit (acquires the same potential energy) must have higher kinetic energy in the balance, and needs to bleed off speed in the gravity assist.</description>
		<content:encoded><![CDATA[<p>#12 Wayne, </p>
<p>Thanks for the kind words, but truth is I messed up big time as I glossed over the potential energy loss before acquiring the orbit. Luckily toasterhead listened to saner advice.</p>
<p>I like your argument, because then I don&#8217;t need to analyze orbital motion for its effect on energy balance. </p>
<p>Yet another way to see that a round orbit is the least energy state is to realize that this is the reason for hydrostatic spherical shape of planets. [More generally, this condition must mean stability of this type of field, or, say, planets would split and sunder.] So the probe going in another trajectory at the moment it hits Mercury orbit (acquires the same potential energy) must have higher kinetic energy in the balance, and needs to bleed off speed in the gravity assist.</p>
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		<title>By: Fischblog</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2009/09/27/messenger-three-days-out-from-mercury/comment-page-1/#comment-216321</link>
		<dc:creator>Fischblog</dc:creator>
		<pubDate>Mon, 28 Sep 2009 21:21:28 +0000</pubDate>
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		<description>&lt;strong&gt;...&lt;/strong&gt;

Merkur, der kleinste und sonnenn&#228;chste Planet des Sonnensystems, geh&#246;rt zu den am wenigsten erforschten Planeten des Sonnensystems. Mit knapp 4900 Kilometer Durchmesser ist er etwa anderthalb Mal so gro&#223; wie der Erdmond, und mit seiner ...</description>
		<content:encoded><![CDATA[<p><strong>&#8230;</strong></p>
<p>Merkur, der kleinste und sonnenn&auml;chste Planet des Sonnensystems, geh&ouml;rt zu den am wenigsten erforschten Planeten des Sonnensystems. Mit knapp 4900 Kilometer Durchmesser ist er etwa anderthalb Mal so gro&szlig; wie der Erdmond, und mit seiner &#8230;</p>
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		<title>By: NelC</title>
		<link>http://blogs.discovermagazine.com/badastronomy/2009/09/27/messenger-three-days-out-from-mercury/comment-page-1/#comment-216222</link>
		<dc:creator>NelC</dc:creator>
		<pubDate>Mon, 28 Sep 2009 16:07:07 +0000</pubDate>
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		<description>But, Mus@2, everybody knows there aren&#039;t any stars that close to the Sun. 

;p</description>
		<content:encoded><![CDATA[<p>But, Mus@2, everybody knows there aren&#8217;t any stars that close to the Sun. </p>
<p>;p</p>
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