Comments on: Succumbing to LaTeX

By: chi

chi — Tue, 13 Oct 2009 01:41:06 +0000

[tex]xinmathbb{R}[/tex]

By: macho

macho — Fri, 03 Jul 2009 00:21:01 +0000

$latex GeV/cm^3$

By: macho

macho — Fri, 03 Jul 2009 00:20:19 +0000

$latex cm^3$

By: macho

macho — Fri, 03 Jul 2009 00:17:07 +0000

adding a link:

Google News

By: Successful Researcher: How to Become One

Successful Researcher: How to Become One — Tue, 26 May 2009 17:40:03 +0000

Just a test: $latex E=m c^2$

By: notaquant

notaquant — Sun, 10 May 2009 17:53:55 +0000

[tex]
i\hbar\frac{\partial\psi}{\partial t}(t,x)=-\frac{\hbar^2}{2m}\nabla^2\psi(t,x)+V(t,x)\psi(t,x)
[/tex]

By: notaquant

notaquant — Sun, 10 May 2009 17:52:26 +0000

$latex
i\hbar\frac{\partial\psi}{\partial t}(t,x)=-\frac{\hbar^2}{2m}\nabla^2\psi(t,x)+V(t,x)\psi(t,x)
$

By: hmm

hmm — Sat, 04 Apr 2009 19:11:07 +0000

[tex]R_{\mu\nu}-\frac{1}{2}Rg_{\mu\nu}=8\pi G T_{\mu\nu}[/tex]

By: asdfhgh

asdfhgh — Sun, 29 Mar 2009 11:05:27 +0000

$latex | \psi \rangle $

By: asdfhgh

asdfhgh — Sun, 29 Mar 2009 11:04:26 +0000

[tex]| \psi \rangle[/tex]

By: notaquant

notaquant — Tue, 03 Feb 2009 19:45:52 +0000

$latex \frac{\partial\psi}{\partial t}(t,x)=-\frac{\partial^2\psi}{\partial x^2}(t,x)+V(t,x)\psi(t,x)$

By: andy.s

andy.s — Sat, 17 Jan 2009 22:36:57 +0000

I look forward to it Sean. But I bet you’d sell more if you explained it all to your dog.

Also: re entropy.

Consider a muon. Before it decays is structureless and just like a stable particle in terms of properties, but when it decays there is then more complexity in the universe than before etc – how can entropy be coherently defined for such entities

Not sure if entropy would increase in this reaction. Muon decay goes like $latex \mu^- \to \nu_\mu + W^- \to \nu_\mu + e^- + \bar{\nu_e}$. That reaction should be reversible, and in chemistry, IIRC, a reversible reaction does not increase entropy. I don’t know, maybe it’s different with particles.

By: andy.s

andy.s — Fri, 09 Jan 2009 01:01:24 +0000

$latex \LaTeX$

By: Brad

Brad — Wed, 31 Dec 2008 19:15:51 +0000

Oh well, it looks squished.

By: Brad

Brad — Wed, 31 Dec 2008 19:15:35 +0000

Oh, right…

$latex i \hbar \frac{\partial \boldsymbol{\Psi}}{\partial t} = \Big[ - \frac{\hbar^2}{2m} \nabla^2 + V \Big] \boldsymbol{\Psi} \displaystyle $

By: Brad

Brad — Wed, 31 Dec 2008 19:14:50 +0000

$latex i \hbar \frac{\partial \boldsymbol{\Psi}}{\partial t} = \Big[ - \frac{\hbar^2}{2m} \nabla^2 + V \Big] \boldsymbol{\Psi} $

It worked in Wikipedia:Sandbox, let’s see if it works here.

By: A Student

A Student — Fri, 31 Oct 2008 01:12:16 +0000

$latex P(A\cup B)$

By: A Student

A Student — Fri, 31 Oct 2008 01:11:18 +0000

$latex P(A\cupB)$

By: A Student

A Student — Fri, 31 Oct 2008 01:10:26 +0000

$latex P(A \cup B)$

By: A Student

A Student — Fri, 31 Oct 2008 01:09:46 +0000

$latex P(A \cup B)[\tex]